A "saddle point" refers to the maximum matrix element value of the element at that position, the minimum on the column on the line.
This problem requires programming, seeking a given n-order square matrix saddle point.
Input formats:
The first input line is given a positive integer n (1≤n≤6). Then n lines of n integers are given, separated by a space therebetween.
Output formats:
Output in "lower line marked column index" (index starting from 0) of the output format saddle point position in a row. If the saddle point does not exist, the output "NONE". Title ensure a given matrix at most one saddle point.
Sample Input 1:
4
1 7 4 1
4 8 3 6
1 6 1 2
0 7 8 9
Output Sample 1:
2 1
Sample Input 2:
2
1 7
4 1
Output Sample 2:
NONE
answer:
#include<stdio.h>
int main(){
int n,max,min,a[10][10];
scanf("%d",&n);
for(int i=0;i<n;i++){
max=a[i][0];
for(int j =0;j<n;j++){
scanf("%d",&a[i][j]);
if(a[i][j]>max){
max = a[i][j];
a[i][9] = max;
}
}
}
for(int j=0;j<n;j++){
min=a[0][j];
for(int i = 0;i<n;i++){
if(a[i][j]<min){
min = a[i][j];
a[9][j] = min;
}
}
}
int flag=0;
for(int i = 0;i<n;i++){
for(int j = 0;j<n;j++){
if(a[i][9]==a[9][j]){
printf("%d %d",i,j);
flag=1;
}
}
}
if(flag==0) printf("NONE");
return 0;
}
Always make life difficult for a test point. .