The title requires quadratic root mono-, result 2 decimal places.
Input formats:
3 are given the input floating-point coefficients in a row a, b, c, separated by a space.
Output formats:
The coefficients, the output different results:
1) If the equation has two real roots are not equal, then each output line of a root, the first big small;
2) If the equation has two complex roots are not equal, then each line in the format "real imaginary + i" outputs a root, the output of the first imaginary part is positive, the output of the imaginary part is negative;
3) If equation has only one root, the root directly output;
4) If the coefficient is 0, then output "Zero Equation";
5) If a and b is 0, c is not 0, then output "Not An Equation".
Sample Input 1:
2.1 8.9 3.5
Output Sample 1:
-0.44
-3.80
Sample Input 2:
1 2 3
Output Sample 2:
-1.00+1.41i
-1.00-1.41i
Sample Input 3:
0 2 4
Sample Output 3:
-2.00
Input Sample 4:
0 0 0
Output Sample 4:
Zero Equation
Input Sample 5:
0 0 1
Output Sample 5:
Not An Equation
By Roots formula, but do not pay attention to pure imaginary root a minus sign in front of 0.
Code:#include <stdio.h> #include <math.h> int main() { double a,b,c; scanf("%lf%lf%lf",&a,&b,&c); if(a == 0 && b == 0 && c == 0) printf("Zero Equation\n"); else if(a == 0 && b == 0 && c != 0) printf("Not An Equation\n"); else if(a == 0) printf("%.2f\n",-c / b); else { double det = b * b - 4 * a * c,aa = a * 2; if(det == 0) printf("%.2f\n",-b / aa); else if(det > 0) printf("%.2f\n%.2f\n",(-b + sqrt(det)) / aa,(-b - sqrt(det)) / aa); else printf("%.2f+%.2fi\n%.2f-%.2fi\n",(b == 0 ? b : -b) / aa,sqrt(-det) / aa,(b == 0 ? b : -b) / aa,sqrt(-det) / aa); } return 0; }