LeetCode 844. Backspace String Compare (比较含退格的字符串)

题目标签:Stack

  用的最基本的办法,设两个 stack,最后比较两个stack 是否相等。

Java Solution:

Runtime:  2 ms, faster than 44.83% 

Memory Usage: 38.2 MB, less than 6.06%

完成日期:02/15/2020

关键点:stack

class Solution {
    public boolean backspaceCompare(String S, String T) {
        Stack<Character> stack1 = new Stack<>();
        Stack<Character> stack2 = new Stack<>();
        
        // stack1
        for(char c : S.toCharArray()) {
            if(c != '#')
                stack1.push(c);
            else if(!stack1.empty()) 
                stack1.pop();
        }
        // stack2
        for(char c : T.toCharArray()) {
            if(c != '#')
                stack2.push(c);
            else if(!stack2.empty()) 
                stack2.pop();
        }
        
        return stack1.equals(stack2);
    }
}

参考资料:n/a

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题目来源:https://leetcode.com/

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转载自www.cnblogs.com/jimmycheng/p/12315598.html