X+一个数为平方根，X+另一个数还为平方根

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因式分解算法

int element = Num;       //用于因式分解的数
int flag = element;
Dictionary<int, int> factor = new Dictionary<int, int>(); //Value>Key
for (int i = 1; i < flag ; i++)
{
	if (element % i == 0) //能整除
	{
	   factor[i] = element / i;
	}
	flag = element / i;
}

X+一个数为平方根，X+另一个数还为平方根的C#算法：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace YinShiFenJie
{
    class Program
    {
        static void Main(string[] args)
        {
            Console.WriteLine("请输入了两个数：");
            string num = Console.ReadLine();
            string[] N = num.Split(',');
            int num1 = Convert.ToInt32(N[0]);
            int num2 = Convert.ToInt32(N[1]);
            int element = Math.Abs(num1-num2);       //两数的差的平方
            int a=0, b=0;
            int flag = element;
            Dictionary<int, int> factor = new Dictionary<int, int>(); //Value>Key
            for (int i = 1; i < flag ; i++)
            {
                if (element % i == 0) //能整除
                {
                    factor[i] = element / i;
                }
                   flag = element / i;
            }
            Console.WriteLine(element + "的因数有：");
            foreach (KeyValuePair<int, int> item in factor)
            {
                Console.WriteLine(item.Key+","+item.Value);
                if ((item.Key + item.Value) % 2 == 0)
                {
                    a = (item.Value + item.Key) / 2;
                    b = (item.Value - item.Key) / 2;
                    Console.WriteLine("该因式对为："+a+","+b+"的和差积");
                    Console.WriteLine("这个数可以为：" + ((a * a) + (b * b) - num1 - num2) / 2);
                }
            }
            
            Console.ReadKey();
        }
    }
}