贝塞尔曲线整理

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<canvas id="myCanvas" width="500" height="500" style="border:1px solid red"></canvas>
<script type="text/javascript">
/*
参考维基百科
http://zh.wikipedia.org/wiki/%E8%B2%9D%E8%8C%B2%E6%9B%B2%E7%B7%9A
*/
function Point2D(x,y){
  this.x=x||0.0;
  this.y=y||0.0;
}
/*
 cp在此是四個元素的陣列:
 cp[0]為起始點,或上圖中的P0
 cp[1]為第一個控制點,或上圖中的P1
 cp[2]為第二個控制點,或上圖中的P2
 cp[3]為結束點,或上圖中的P3
 t為參數值,0 <= t <= 1
*/
function PointOnCubicBezier( cp, t )
{
  var  ax, bx, cx;
  var  ay, by, cy;
  var  tSquared, tCubed;
  var  result = new Point2D ;
  /*計算多項式係數*/
  cx = 3.0 * (cp[1].x - cp[0].x);

  bx = 3.0 * (cp[2].x - cp[1].x) - cx;
  ax = cp[3].x - cp[0].x - cx - bx;
  cy = 3.0 * (cp[1].y - cp[0].y);
  by = 3.0 * (cp[2].y - cp[1].y) - cy;
  ay = cp[3].y - cp[0].y - cy - by;
  /*計算位於參數值t的曲線點*/
  tSquared = t * t;
  tCubed = tSquared * t;
  result.x = (ax * tCubed) + (bx * tSquared) + (cx * t) + cp[0].x;
  result.y = (ay * tCubed) + (by * tSquared) + (cy * t) + cp[0].y;
  return result;
}
/*
 ComputeBezier以控制點cp所產生的曲線點,填入Point2D結構的陣列。
 呼叫者必須分配足夠的記憶體以供輸出結果,其為<sizeof(Point2D) numberOfPoints>
*/
function ComputeBezier( cp, numberOfPoints, curve )
{
  var  dt;
  var  i;
  dt = 1.0 / ( numberOfPoints - 1 );
  for( i = 0; i < numberOfPoints; i++)
    curve[i] = PointOnCubicBezier( cp, i*dt );
}

//四个控制中点
var cp=[
  //new Point2D(20, 0), new Point2D(100, 200), new Point2D(300, -200), new Point2D(400, 0)
  new Point2D(500, 0), new Point2D(400,100), new Point2D(50, -350), new Point2D(0, -500)
];
//控制速度
var numberOfPoints=100;
var curve=[];
ComputeBezier( cp, numberOfPoints, curve );


var c=document.getElementById("myCanvas");
    var ctx=c.getContext("2d");

ctx.beginPath()
for(var i=0;i<curve.length;i++)
{
    console.log(curve[i].x)
    
    ctx.lineTo(curve[i].x,curve[i].y);
}
    ctx.strokeStyle="green";
        ctx.stroke();

/*var i=0, dot=document.getElementById("dotMove");
setInterval(function (){
  var j = (i<100)?i:(199-i);
  dot.style.left=curve[j].x+'px';
  dot.style.top=100-curve[j].y+'px';
  if(++i==200)i=0;
}, 50);*/
</script>

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转载自blog.csdn.net/qq_22936647/article/details/82730092