Given an array and a value, remove all instances of that value in-place and return the new length.
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given nums = [3,2,2,3], val = 3, Your function should return length = 2, with the first two elements of nums being 2.代码如下:
int removeElement(int* nums, int numsSize, int val) { int i,j,k; for(i=0;i<numsSize;i++) { if(nums[i]==val) { for(j=i+1;j<numsSize;j++) { nums[i]=nums[j]; } numsSize--; i--; } } return numsSize; }