Redis订阅&发布以及python代码实现

A:命令行

服务器端

192.168.1.168:7000> subscribe foo bar

Reading messages... (press Ctrl-C to quit)

1) "subscribe"

2) "redisChat"

3) (integer) 1

1

1) "message"

2) "redisChat"

3) "hello!"

1) "message"

2) "redisChat"

3) "my name is alex!"

客户端

127.0.0.1:7000> publish foo  "hello!"

(integer) 1

127.0.0.1:7000> publish bar "my name is alex!"

(integer) 1

127.0.0.1:7000> publish bar "我是中文!"

(integer) 1

127.0.0.1:7000> 

B:集群Python

pip install redis-py-cluster

---------------------------------------------------------------

服务器端

from rediscluster import StrictRedisCluster
startup_nodes = [{"host": "192.168.1.168", "port": "7000"}]
rc = StrictRedisCluster(startup_nodes=startup_nodes, decode_responses=True)
ps=rc.pubsub()
ps.subscribe(['foo', 'bar'])
for item in ps.listen():
if item['type'] == 'message':
print item['data']

客户端

from rediscluster import StrictRedisCluster
startup_nodes = [{"host": "192.168.1.168", "port": "7000"}]
rc = StrictRedisCluster(startup_nodes=startup_nodes, decode_responses=True)
ps = rc.pubsub()
ps.subscribe(['foo', 'bar'])
rc.publish('foo', 'hello foo')
rc.publish('bar', 'hello bar')

C:非集群python

pip install redis
-------------------------------------------------------------

import redis
rc = redis.Redis(host='127.0.0.1')
ps = rc.pubsub()
ps.subscribe(['foo', 'bar'])
for item in ps.listen():
if item['type'] == 'message':
print item['data']

import redis
rc = redis.Redis(host='127.0.0.1')
ps = rc.pubsub()
ps.subscribe(['foo', 'bar'])
rc.publish('foo', 'hello foo')
rc.publish('bar', 'hello bar')