课后总结

package Random_array;

public class test {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
        long seed = System.currentTimeMillis();// 种子
        int i;
        int count = 0;
        // Modulus=231-1=int.MaxValue
        // Multiplier=75=16807
        long random = (16807 * seed) % Integer.MAX_VALUE;
        for (i = 1; i <= 1000; i++) {
            random = (16807 * random) % Integer.MAX_VALUE;
            System.out.print(random + " ");
            count++;
            if (count % 5 == 0)
            	 System.out.println();
        }
    }
}

package first;

public class MethodOverload {

    public static void main(String[] args) {
        System.out.println("The square of integer 7 is " + square(7));
        System.out.println("\nThe square of double 7.5 is " + square(7.5));
    }

    public static int square(int x) {
        return x * x;
    }

    public static double square(double y) {
        return y * y;
    }
}

1.上述示例代码展示了Java的“方法重载(overload)
■满足以下条件的两个或多个方法构成“重载”关系:
(1)方法名相同;
(2)参数类型不同，参数个数不同，或者是参数类型的顺序不同。
■注意:返回值不作为方法重载的判断条件

查看JDK中System.out.println()方法的部分内容

 /**
     * Prints an integer and then terminate the line.  This method behaves as
     * though it invokes <code>{@link #print(int)}</code> and then
     * <code>{@link #println()}</code>.
     *
     * @param x  The <code>int</code> to be printed.
     */
    public void println(int x) {
        synchronized (this) {
            print(x);
            newLine();
        }
    }
   /**
     * Prints a String and then terminate the line.  This method behaves as
     * though it invokes <code>{@link #print(String)}</code> and then
     * <code>{@link #println()}</code>.
     *
     * @param x  The <code>String</code> to be printed.
     */
    public void println(String x) {
        synchronized (this) {
            print(x);
            newLine();
        }
    }

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