#用列表+循环实现,并包装成函数 def pySum(n): a = list(range(10)) b = list(range(0, 50, 5)) c = [] for i in range(len(a)): c.append(a[i] ** 2 + b[i] ** 3) return(c) print(pySum(10)) #用numpy实现,并包装成函数 import numpy def npSum(n): a = numpy.arange(10) b = numpy.arange(0, 50, 5) c = a + b return(c) print(npSum(10)) #对比两种方法实现的效率,给定一个较大参数n,用运行函数前后的timedelta表示 from datetime import datetime start = datetime.now() pySum(100000) delta = datetime.now()-start print(delta)
start= datetime.now() npSum(100000) delta = datetime.now()-start print(delta)
老师我的numpy 不知道为什么装不上,我就借鉴了同学的,我在教室里已经快做完了