LeetCode 495. 提莫攻击

因为时间序列有序，从后往前遍历一次，总时间要么是前一个时间点减后一个时间点，要么是吃满中毒持续时间。

class Solution
{
public:
    int findPoisonedDuration(vector<int>& timeSeries, int duration)
    {
        int count = 0;
        for(int i = timeSeries.size()-1; i>=0; i--)
        {
            if(i == (timeSeries.size()-1))
                count = duration;
            else{
            if(timeSeries[i+1] - timeSeries[i]<duration)
                count += timeSeries[i+1] - timeSeries[i];
            else
                count += duration;
            }
        }
        return count;
    }
};

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