J - Square Coins HDU - 1398
People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (=17^2), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ..., and 289-credit coins, are available in Silverland.
There are four combinations of coins to pay ten credits:
ten 1-credit coins,
one 4-credit coin and six 1-credit coins,
two 4-credit coins and two 1-credit coins, and
one 9-credit coin and one 1-credit coin.
Your mission is to count the number of ways to pay a given amount using coins of Silverland.Input
The input consists of lines each containing an integer meaning an amount to be paid, followed by a line containing a zero. You may assume that all the amounts are positive and less than 300.
Output
For each of the given amount, one line containing a single integer representing the number of combinations of coins should be output. No other characters should appear in the output.
Sample Input
2 10 30 0Sample Output
1 4 27
#include<cstdio>
#include<stack>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
#include<cstring>
#include<string>
#include<map>
#include<iostream>
#include<cmath>
using namespace std;
#define inf 0x3f3f3f3f
typedef long long ll;
const int N=444;
const int MOD = 1e5+ 7;
int a[N],t[N];
int main()
{
int n;
while(scanf("%d",&n)!=EOF)
{
if(n==0)
break;
memset(a,0,sizeof(a)); /
memset(t,0,sizeof(t));
a[0]=1;
for(int i=1; i*i<=n; i++)
{
for(int j=0; j<=n; j++)
{
if(a[j])
{
for(int k=0; j+k<=n;k+=i*i)
{
t[j+k]+=a[j];
}
}
}
memcpy(a,t,sizeof(a));
memset(t,0,sizeof(t));
}
printf("%d\n",a[n]);
}
return 0;
}