python实现mqtt订阅、发布

python实现mqtt订阅、发布

发布

# -*- coding: utf-8 -*-
import paho.mqtt.client as mqtt
import json
import time

HOST = "xxxxxx"
PORT = 1883
client_id = time.strftime('%Y%m%d%H%M%S',time.localtime(time.time()))
if __name__ == '__main__':
    client = mqtt.Client(client_id)
    client.username_pw_set("test", "test")
    client.connect(HOST, PORT, 60)
    msg = input("please input you send message：")
    client.publish("利川", msg, qos=0)     # 发送消息

订阅

#coding=utf-8
import paho.mqtt.client as mqtt
import time
import sys
reload(sys)
sys.setdefaultencoding('utf-8')
HOST = "xxxx"
PORT = 1883
def client_loop():
    client_id = "0bd981c5-a055-4196-8b7f-efb9f7a4d6ac"
    client = mqtt.Client(client_id)    # ClientId不能重复，所以使用当前时间
    client.username_pw_set("test", "test")  # 必须设置，否则会返回「Connected with result code 4」
    client.on_connect = on_connect
    client.on_message = on_message
    client.connect(HOST, PORT, 60)
    client.loop_forever()

def on_connect(client, userdata, flags, rc):
    client.subscribe("test")

def trun(a):
    
    if(a == "打开"):
        print("我要开灯了")
    else:
        print("我要关灯了")

def on_message(client, userdata, msg):

    print(msg.topic+" "+msg.payload.decode("utf-8"))
    trun(msg.payload.decode("utf-8"))

if __name__ == '__main__':
    global a
    a = -1
    client_loop()

注意：用户id不能重复，所以要随机生成。