Given a non-negative index k where k ≤ 33, return the kth index row of the Pascal's triangle.
Note that the row index starts from 0.
In Pascal's triangle, each number is the sum of the two numbers directly above it.
Example:
Input: 3 Output: [1,3,3,1]
Follow up:
Could you optimize your algorithm to use only O(k) extra space?
Solution: only using O(k), update the elements in the array, we need temp to keep the previous element
using list to set : list.set(index, num);
class Solution { public List<Integer> getRow(int rowIndex) { List<Integer> res = new ArrayList<>(); res.add(1); for(int i = 1; i<=rowIndex; i++){ int temp = res.get(0);//previous element for(int j = 1; j<i; j++){ int k = res.get(j); res.set(j, k+temp); temp = k; } res.add(1); } return res; } }