Javaでアルファベット順に配列をソート

マリウスクズマ：

私のプログラムでは、私はグループのダンスグループのパターンと、その後のダンサーを以下のCSVファイルからデータを読んでいます。私はアルファベット順にダンサーの名前をソートするために苦労しています。

public String listAllDancesAndPerformers() {

    // get CSV file for dances Data
    ArrayList<String> dancesData = getCSV("src/csvFiles/danceShowData_dances.csv");

    int lineNumber = 0;
    String result = "";

    //for each line in dances csv file
    for (String line : dancesData) {

        //split into two sections - [0] is name of dance & [1] is dancers
        String[] splitByTab = line.split("\t");


         //take the dancers [1] of splitByTab and split it by commas
         // this makes that seperatedNames[1], [2] etc are all the dancers
         //and i am supposed to sort the seperated names to print out alphabetticaly
        String[] separatedNames = splitByComma(splitByTab[1]);


        lineNumber++;
        result += lineNumber + ": ";
        result += (splitByTab[0].trim()) + "\n";



        result += (listAllDancersIn(splitByTab[0].trim())) + "\n";


    }

    return result;
}

リストダンス名の入力を受け取り、その後、CSVファイルからの読み込みの内側のダンサーが続くダンスの名前を出力し、すべてのダンサー方法

public String listAllDancersIn(String dance) {
    // get CSV file for dances Data
    ArrayList<String> dancesData = getCSV("src/csvFiles/danceShowData_dances.csv");

    String result = "";

    // for each line in dances csv file
    for (String line : dancesData) {

        // split into two sections - [0] is name of dance & [1] is dancers
        String[] splitByTab = line.split("\t");

        splitByTab[0] = splitByTab[0].trim();

        // if name of dance matches given dance name
        if (splitByTab[0].equals(dance)) {

            // split names of dancers into individual strings
            String[] separatedNames = splitByComma(splitByTab[1]);

            // iterate through names
            for (int i = 0; i < separatedNames.length; i++) {
                // append result with output of getDanceGroupMembers (and trim input)
                result += ", " + getDanceGroupMembers(separatedNames[i].trim());
            }
        }
    }

    // remove leading comma and space
    result = result.substring(2);

    return result;
}

プラサドKarunagoda：

マリウスは、あなたが意図したとおりのコードが動作する以下かどうかを確認します。

import java.util.ArrayList;
import java.util.Collections;

public class SortDancers {

    public static void main(String[] args) {

        System.out.println(new SortDancers().listAllDancesAndPerformers());
    }

    public String listAllDancesAndPerformers() {

        ArrayList<String> dancesData = new ArrayList<String>();
        dancesData.add("Dance1 \t Kelly, Andrew, Nathan");
        dancesData.add("Dance2 \t John, Sally, Kevin, Abby");
        dancesData.add("Dance3 \t Laura, Benny, Jane");
        // I assume you get this kind of data from getCSV()

        int lineNumber = 0;
        String result = "";

        for (String line : dancesData) {

            String[] splitByTab = line.split("\t");

            String[] separatedNames = splitByTab[1].split(",");

            lineNumber++;
            result += lineNumber + ": ";
            result += (splitByTab[0].trim()) + "\n";

            ArrayList<String> separatedNamesList = new ArrayList<String>();
            for (int i = 0; i < separatedNames.length; i++) {
                separatedNamesList.add(separatedNames[i].trim());
            }

            Collections.sort(separatedNamesList);
            result += String.join(", ", separatedNamesList);
            result += "\n";
        }

        return result;
    }
}