杭电HDOJ1012 u Calculate e

#include<stdio.h>
int f(int n)
{
 return n<=1?1:n*f(n-1);
}
int main()
{
 const int n=9;
 double sum=0;
 printf("n e\n- -----------\n");
 for(int i=0;i<=n;i++)
 {
  //printf("1/f(%d)=%f\n",i,1/(double)f(i));
  //if(!i)
  sum+=1/(double)f(i);
  if(i<=1)printf("%d %d\n",i,(int)sum);
  else if(i==2)printf("%d %.1f\n",i,sum);
  else
  printf("%d %.9f\n",i,sum);
 }
 return 0;
}

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転載: blog.csdn.net/lollo01/article/details/52998231