剑指 Offer 32:从上到下打印二叉树

剑指 Offer 32 - I. 从上到下打印二叉树

题目链接

class Solution {
    
    
public:
    vector<int> levelOrder(TreeNode* root) {
    
    
        if(!root) return {
    
    };
        queue<TreeNode*> queue;
        vector<int> res;
        queue.push(root);
        while(!queue.empty()){
    
    
            TreeNode* cur=queue.front();
            queue.pop();
            res.push_back(cur->val);
            if(cur->left){
    
    
                queue.push(cur->left);
            }
            if(cur->right){
    
    
                queue.push(cur->right);
            }
        }
        return res;
    }
};

剑指 Offer 32 - II. 从上到下打印二叉树 II

题目链接

class Solution {
    
    
public:
    vector<vector<int>> levelOrder(TreeNode* root) {
    
    
        if(!root) return {
    
    };
        queue<TreeNode*> queue;
        queue.push(root);
        vector<vector<int>> res;
        while(!queue.empty()){
    
    
            int l=queue.size();
            vector<int> tmp;
            for(int i=0;i<l;i++){
    
    
                TreeNode* cur=queue.front();
                queue.pop();
                tmp.push_back(cur->val);
                if(cur->left){
    
    
                    queue.push(cur->left);
                }
                if(cur->right){
    
    
                    queue.push(cur->right);
                }
            }
            res.push_back(tmp);
        }
        return res;
    }
};

剑指 Offer 32 - III. 从上到下打印二叉树 III

题目链接

class Solution {
    
    
public:
    vector<vector<int>> levelOrder(TreeNode* root) {
    
    
        if(!root) return {
    
    };
        queue<TreeNode*> queue;
        queue.push(root);
        vector<vector<int>> res;
        int flag=0;
        while(!queue.empty()){
    
    
            int l=queue.size();
            vector<int> tmp;
            for(int i=0;i<l;i++){
    
    
                TreeNode* cur=queue.front();
                queue.pop();
                tmp.push_back(cur->val);
                if(cur->left){
    
    
                    queue.push(cur->left);
                }
                if(cur->right){
    
    
                    queue.push(cur->right);
                }
            }
            if(flag&1==1){
    
    
                reverse(tmp.begin(),tmp.end());
            }
            res.push_back(tmp);
            flag++;
        }
        return res;
    }
};

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転載: blog.csdn.net/qq_21539375/article/details/121557673