newFixedThreadPool 线程池实例

1、公司系统中遇到一个excel导出由于数据量过大而比较慢的场景,所以决定进行多线程处理,提高代码的执行效率

ExecutorService pool = Executors.newFixedThreadPool(6);

经过对比 打算采用newFixedThreadPool初始化线程池,多线程执行完成后 依然要回到主线程中继续执行,所有还要有CountDownLatch 用来实现此场景

	private void mobileData(List<Customer> list){
    
    
		ExecutorService pool = Executors.newFixedThreadPool(6);
		final CountDownLatch latch1 = new CountDownLatch(list.size());
		for (Customer customer : list) {
    
    
			Runnable run = new Runnable() {
    
    
				@Override
				public void run() {
    
    
					try {
    
    
						if(customer.getTelephone() != null && customer.getTelephone().length()>0){
    
    
							try {
    
    
								PhoneNumberLookup phoneNumberLookup = new PhoneNumberLookup();
								String province = phoneNumberLookup.lookup(customer.getTelephone())
										.map(PhoneNumberInfo::getAttribution)
										.map(Attribution::getProvince)
										.orElse("未知");
								customer.setArea(province);
							} catch (RuntimeException e) {
    
    
								System.out.println("=================号码:"+customer.getTelephone());
							}
						}
					} catch (Exception e) {
    
    
					}finally {
    
    
						latch1.countDown();
					}
				}
			};
			pool.execute(run);
		}
		try {
    
    
			latch1.await();
		} catch (InterruptedException e) {
    
    
			e.printStackTrace();
		}
		pool.shutdown();
	}

初始化6个线程,分别由cpu去调配完成 该list参数的迭代,业务代码主要去识别list对象中的手机号码归属地,每个线程代码块执行完成后 都要进行latch1.countDown(); 使计数器减一,直到该计数器为0 latch1.await(); 阻塞就结束了,多线程执行逻辑就完成了,可继续回到主线程,这样就实现了 多线程并发处理任务完成后 继续主线程的逻辑。

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Origin blog.csdn.net/u012565281/article/details/120547058
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