题目的意思就是求一个数的n阶乘
#include"bits/stdc++.h"
#define ll long long
#define inf 1000000007
using namespace std;
ll t,n;
int main()
{
cin >> t;
while(t--)
{
cin >> n;
ll sum = 1;
for(int i=2;i<=n*2-1;i++){
sum = sum *i;
sum=sum % inf;
}
sum = (sum*n)%inf;
cout << sum << endl;
}
return 0;
}