Learning immediately: https://edu.csdn.net/course/play/20589/257728?utm_source=blogtoedu
1. Operator Precedence
A: ++ - + (right) - (minus sign)
Two: * /%
Three: + -
Four: = * = + / = - = =%
int var1, var2 = 5, var3 = 6;
var1 = var2++ * --var3 + ++var2 * var3--; //5 * 5 + 7 * 5 = 60 //一元运算符优先级最高,所以优先计算
2. The high priority within the brackets, can be nested, must occur in pairs
int n4 = 3 * ((5 + 8) / 2 + 9) % 2; //3 * (13 /2 + 9) % 2 = 1