Description
Given an undirected connected graph, vertices numbered from 0 to n-1, with a breadth-first search (BFS) traversal, traverse output sequence starting from a vertex. (With the same layer adjacent to a node point, a small number of nodes first traversal)
the Input
The first line input integer n (0 <n <100) , indicates the number of data sets.
For each test, the first three rows are integers k, m, t (0 < k <100,0 <m <(k-1) * k / 2,0 <t <k), expressed edges m , k vertices, t is the starting vertex traversal.
The following m lines, each line separated by a space of two integers u, v, represents a connector u, v vertices undirected edges.
Output
There are n output lines, an output corresponding to n groups, each separated by spaces behavior of integers k, corresponding to a set of data representing the results of the BFS traversal.
Sample
Input
1
6 7 0
0 3
0 4
1 4
1 5
2 3
2 4
3 5
Output
0 3 4 2 5 1
Hint
In adjacency matrix as a storage structure.
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<malloc.h>
#include<queue>
using namespace std;
int Map[110][110],vis[110];
int n,m;
void bfs(int t)
{
queue<int>q;
vis[t] = 1;
q.push(t);
int flag = 0;
while(!q.empty())
{
int k = q.front();
q.pop();
if(flag == 0)
{
printf("%d",k);
flag = 1;
}
else
printf(" %d",k);
for(int i=0;i<m;i++)
{
if(!vis[i]&&Map[k][i])
{
vis[i] = 1;
q.push(i);
}
}
}
}
int main()
{
int t,p;
int u,v;
scanf("%d",&t);
while(t--)
{
scanf("%d %d %d",&n,&m,&p);
memset(vis,0,sizeof(vis));
memset(Map,0,sizeof(Map));
for(int i=0;i<m;i++)
{
scanf("%d %d",&u,&v);
Map[u][v] = 1;
Map[v][u] = 1;
}
bfs(p);
printf("\n");
}
return 0;
}