Continuous input string, by the length of the output string array to a new resolution after each string 8; 8 is not an integer multiple of the length of a string of numbers 0 Please back up, not the empty string processing.

This problem mainly has the idea of ​​direct experience: the direction of thinking to solve the problem is more convenient

package com.pagination.plus.workTrain;

import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStreamReader;

/**
 *连续输入字符串,请按长度为8拆分每个字符串后输出到新的字符串数组;
 * 长度不是8整数倍的字符串请在后面补数字0,空字符串不处理。
 * 连续输入字符串(输入2次,每个字符串长度小于100)
 * 输出到长度为8的新字符串数组
*/
public class Main {
    public static void main(String[] args) throws IOException {
        //BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(new FileInputStream("D:\\JavaData\\tmp/input.txt")));
        //Scanner sc = new Scanner(System.in);


        String s = null;
        while ((s=bufferedReader.readLine())!=null) {
            StringBuilder sb = new StringBuilder();
            String str = s.trim();
            for (int i=0;i<str.length();i++) {
                if(' '!=str.charAt(i)){
                    sb.append(str.charAt(i));
                }
            }
            //System.out.println(sb.toString());
            //第一种复杂方法,正逻辑处理:考虑先分段在是否补0
        /*    if(sb.length()>0&&sb.length()<8){
                int cout = 8-sb.length();
                while (cout>0){
                    sb.append(0);
                    cout--;
                }
                System.out.println(sb.toString());

            }else
                if(sb.length()==8){
                    System.out.println(sb.toString());
                }else{
                    int segmets = sb.length()/8;
                    int mod =  sb.length()%8;
                    for(int i=0,j=0;i<segmets;i++,j+=8){
                        System.out.println(sb.substring(j,j+8));
                    }
                    if(mod!=0){
                        String substring = sb.substring(sb.length() - mod, sb.length());
                        StringBuilder stringBuilder = new StringBuilder(substring);
                        for(int i=0;i<8-mod;i++){
                            stringBuilder.append(0);
                        }
                        System.out.println(stringBuilder.toString());
                    }
                }*/

        //第二种简单方法,反向思维,首先判断是否需要补0,然后直接一个方法搞定
            if(sb.length()%8!=0){
                for(int i=0;i<8;i++){
                    sb.append(0);
                }
            }
            for(int i=0,j=0;i<sb.length()/8;i++,j+=8){
                System.out.println(sb.substring(j,j+8));
            }






        }




    }


}

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Origin blog.csdn.net/InternetJava/article/details/104793513