#include <stdio.h>
int main()
{
char a[1001]={0},b[1001]={0};
int i=0,j,flag,c=0; //c是没有的珠子数
scanf("%s %s",a,b);
while(b[i])
{
j=0; flag=0;
while(a[j])
{
if(b[i] == a[j])
{
flag = 1;
a[j] = '+'; //随便什么符号都行,只要不属于[0-9]、[a-z]、[A-Z]范围内
break;
}
j++;
}
if(!flag) c++;
i++;
}
if(c)
printf("No %d",c);
else
{
c = strlen(a) - strlen(b);
printf("Yes %d",c);
}
return 0;
}
1039 in the end buying, C
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Origin blog.csdn.net/weixin_43916400/article/details/104522708
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