1226 Problem S- decipher messages - Getting title - string handling -C ++ to achieve

Question S: decipher messages

Time limit: 1 Sec Memory Limit: 32 MB
submitted: 152 solved: 66

Title Description

Bob received a strange message, some of which are all symbols and numbers, but letters deciphering method given above, as follows:

1. The 1 becomes 'A' , 2 becomes 'B' , ..., 26 is changed to 'the Z' ;
2. The '#' into a space;
3. Ignore '-' , the original letter '-' for dividing the digital only.

Now you please help Xiao Ming programming decipher this message.

Entry

A first act input integer C, represents the number of test data sets.
Next C lines of the input character string to be a deciphered string contains only numbers , '-' and '#' , the length does not exceed 100 .

Export

For each set of input, output decipher the text.

Sample input  Copy

4
9#23-9-12-12#19-20-5-1-12#1-20#12-5-1-19-20#15-14-5#10-5-23-5-12
1-14-4#12-5-1-22-5#20-8-5#13-21-19-5-21-13#9-14#20#13-9-14-21-20-5-19
1-6-20-5-18#20-8-5#15-16-5-14-9-14-7#15-6#20-8-5#5-24-8-9-2-9-20-9-15-14
7-15-15-4#12-21-3-11

Sample output  Copy

I WILL STEAL AT LEAST ONE JEWEL
AND LEAVE THE MUSEUM IN T MINUTES
AFTER THE OPENING OF THE EXHIBITION
GOOD LUCK

#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
int main(){
    int T;
    string s;
    scanf("%d",&T);
    getchar();
    while(T--){
        cin>>s;
        for(int i = 0;i < s.size();i++){
            if(s[i]=='#'){
                cout<<" ";
            }
            if(s[i]=='-'){
                continue;
            }
            if(s[i]>='0'&&s[i]<='9'){
                int num=0;
                if(s[i+1]>='0'&&s[i+1]<='9'){
                    num=10*(s[i]-'0')+(s[i+1]-'0');
                    i++;
                }else{
                    num=s[i]-'0';
                }
                char ch='A'+num-1;
                cout<<ch;
            }
        }
        cout<<endl;
    }
}

Code