Arithmetic Primes
1. Problem Description:
Similar 7,37,67,97,107,137,167,197, so that the number of columns consisting of a prime number called arithmetic Prime Number.
Prime Number limit having term generally refers to a number of prime numbers is the number of columns the number of consecutive items, how many consecutive entries may be present up.
2. Title:
Programming arithmetic to find prime numbers less than 100 the number of columns.
Problem-solving ideas:
# 1, sieve find all primes
# 2 for both two compositions, constructor known arithmetic the prime list column a0, a1 item
# 3. Calculated a2, look-up table is determined a2 whether the prime number is a prime number can be constituted prime arithmetic sequence, calculating A3 ...
n=int(input('请输入查找范围:'))
def primeNumber(n):
pt=[True]*n
s=[]
for p in range(2,n):
if not pt[p]:
continue
s.append(p)
for i in range(p*p,n,p):
pt[i]=False
return pt,s
pt,s=primeNumber(n)
for i in range(len(s)):
for j in range(i+1,len(s)):
a0,a1=s[i],s[j]
an = a1 + a1 - a0 #公差相等,前后项相加,等于中间项的2倍
k = []
while an < n and pt[an]: #判断an项是否为素数,如果是则添加到k,打印出来
k.append(an)
an += a1 - a0 #
if k:
print ([a0, a1] +k)