1. The arrangement 1 to n generates the
idea:
introducing cur (cur currently determined first number) to (cur + 1) recursive manner;
Note:
1) the position of the recursive function;.
Code:
#include<cstdio>
#include<iostream>
using namespace std ;
void print_permutation ( int n , int *A , int cur ) {
if ( cur == n ) {
for ( int i = 0 ; i < n ; i ++ ) printf("%d",A[i]) ;
printf("\n") ; //
}
else {
for ( int i = 1 ; i <= n ; i ++ ) {
int ok = 1 ;
for ( int j = 0 ; j < cur ; j ++ ) {
if ( A[j] == i ) {
ok = 0 ;
break ;
}
}
if ( ok == 1 ) {
A[cur] = i ;
print_permutation ( n , A , cur + 1 ) ;
}
}
}
}
int main() {
int n , A[100];
cin>>n ;
for ( int i = 0 ; i < n ; i ++ ) A[i] = i + 1 ;
print_permutation ( n , A , 0 ) ;
return 0 ;
}
2. Generate a predetermined arrangement of array P (re-set)
ideas:
1) P is calculated contains P [i] of number c1, cur-1 th frequency is calculated comprising P [i] of A front c2, comparison, if c1 is greater than c2, the P [i] Alternatively still, through the entire array when P a [cur] each selection;
2) encountered when P [i] = P [i - 1] case, the whole is not performed. it as the beginning of the process.
Such as P = {1,1,1}, if are executed, output 3 . 3 3 = 27 {1,1,1}; performing only the first, output a {1,1,1}, the first cycle, pick the first one, the second cycle, pick the first one, the third cycle, pick the first one; (re-set function when the operation is first number)
Code:
#include<cstdio>
#include<iostream>
#include<cstring>
#include<algorithm>
using namespace std ;
void print_permutation ( int n , int *P , int *A , int cur ) {
if ( cur == n ) {
for ( int i = 0 ; i < n ; i ++ ) printf("%d",A[i]) ;
printf("\n") ;
}
else {
for ( int j = 0 ; j < n ; j ++ )
if ( j == 0 || P[j] != P[j - 1] ) {
int c1 = 0 , c2 = 0 ;
for ( int i = 0 ; i < n ; i ++ ) {
if ( P[j] == P[i] ) c1 ++ ;
}
for ( int i = 0 ; i < cur ; i ++ ) {
if ( A[i] == P[j] ) c2 ++ ;
}
if ( c1 > c2 ) {
A[cur] = P[j] ;
print_permutation ( n , P , A , cur + 1 ) ;
}
}
}
}
int main() {
int n ;
cin>>n ;
int P[n] , A[n] ;
for ( int i = 0 ; i < n ; i ++ ) scanf("%d",&P[i]) ;
print_permutation ( n , P , A , 0 ) ;
return 0 ;
}
3. The next arrangement: next_permutation ()
Code:
#include<cstdio>
#include<algorithm>
using namespace std ;
int main() {
int n ;
scanf ( "%d",&n ) ;
int p[n] ;
for ( int i = 0 ; i < n ; i ++ ) scanf ( "%d", &p[i] ) ;
sort ( p , p + n ) ;
do {
for ( int i = 0 ; i < n ; i ++ ) printf ( "%d",p[i] ) ;
printf ( "\n" ) ;
} while ( next_permutation( p , p + n ) ) ;
return 0 ;
}