This problem requires simple function of the number of seeking a reverse integer.
Function interface definition:
int reverse( int number );
Which must reverse function returns the number of reverse incoming integer number of users.
Referee test program Example:
#include <stdio.h>
int reverse( int number );
int main()
{
int n;
scanf("%d", &n);
printf("%d\n", reverse(n));
return 0;
}
/ * Your code will be embedded here * /
Sample input:
-12340
Sample output:
-4321
在这里插入代码片
int reverse( int number ){
int symbol=1,x,sum=0;
if(number<0){
number=-number;
symbol=-1; //负数先存起来
}
while(number>0){
x = number%10;
sum = sum * 10 +x; //0*10+1//1*10+2//
number/=10;
}
sum*=symbol;
return sum;
}