First seek odd and between 1 and 100, and then seek the even and between 1 and 100
for(int i=1;i<=100;i++)
{
if(i%2 ==0)
{
sum1+=i;
}
else
{
sum2+=i;
}
}
printf ( "is an even number and% d", sum1);
print ( "odd and is the% d", sum2);
A judge is not an odd number, odd gave sum2, or to sum1
Averaging an odd number between 1 and 100
# include<stdio.h>
{
int I = 0;
int sum2 = 0;
float ave = 0;
for(int i = 1; i<=100; i+=1)
{
sum += i;
if ( i % 2) ==1
{
sum2 += i
}
}
ave = (float)(sum2) / sum;
print ( "average is% f", ave);
}
Seeking between odd number 1-100
if every once set up, chanting counter +1
int cnt = 0;
for ( int i = 1; i<=100; i++)
{
if(i%2 == 1)
{
cnt += 1;
}
print ( "odd number is the% d", cnt)
}