PAT (Advanced Level) 1023 Have Fun with Numbers (20分)JAVA实现

tips

with no duplication is not repeated
permutation arrangement
given number given digital
original number original figures

Sample Input:

1234567899

Sample Output:

Yes
2469135798

package PAT_Advanced_Level;

import java.math.BigInteger;
import java.util.Scanner;

public class _1023_Have_Fun_with_Numbers {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		String temp = sc.nextLine();
		// while(true) {
		char[] charA = temp.toCharArray();
		BigInteger big = new BigInteger(temp);
		BigInteger multiply = big.multiply(new BigInteger(2 + ""));
		String target = multiply + "";
		char[] charB = target.toCharArray();
		if (charA.length != charB.length) {
			System.out.println("No");
		} else {
			String s = "";
			for (int i = 0; i < charA.length; i++) {
				for (int j = 0; j < charB.length; j++) {
					if (charA[i] == charB[j]) {
						charA[i] = 's';
						s += "s";
						break;
					}
				}
			}
			// String.valueOf(charA)将char[]转为String
			if (String.valueOf(charA).equals(s)) {
				System.out.println("Yes");
			} else {
				System.out.println("No");
			}

		}
		System.out.println(multiply);

		// }

	}
}