When I die, I see lesson today read head, forgot to send the job, was criticized Noriaki
and chemical operations or messing around directly on the hair
I feel like I've died early, and now is not death, the school will
function
Very easy, there is a lot of overlap between the language of section
Note
the use of certain mathematical functions Previously, to use this statement
import mathBefore using a random number, get another call
import random\ (import \) role is to call a library
such as before
import keywordAnd \ (C ++ \) in the
#include<bits/stdc++.h>similar
And when using the function library, you need to add "name of the library."
For example, the square root function needs to be written
math.sqrt()Without \ (math. \) Will complain
Library:
package features some of
the same library function similar to the function
Absolute value function
\ (abs \) function, when engaged in competition is not very popular (in fact, I was too dishes
print( abs( -19260817 ) ) #顺带一提，19260817是一个质数This function is not \ (math \) library, which is a built-in function
bigger than smaller than
Return true 1, false 0 is returned
without calling \ (math \) library
\ (max, min \) function
\ (max \) literal meaning, the given parameter returns a larger value
, however, and \ (C ++ \) is not the same, can compare multiple
a1 = 1
a2 = 2
a3 = 3
a4 = 4444 #我又来迫害米4达了
print( max( a1, a2, a3, a4 ) )The return value is 4444
\ (min \) Similarly
Instead of calling \ (math \)
power
To calculate \ (2 ^ 5 \)
print( pow( 2, 5 ) )This interesting, pow takes two
The first can be used directly, integer arithmetic
print( pow( 2, 5 ) )The second can not be directly used to invoke \ (math \) library
will retain decimal places
print( math.pow( 2, 5 ) )
Rounding function
Can the provisions of digits, just add a parameter on the line, but without the default, then, is reserved bit integer
print( round( 3.14159 ) ) # 输出3
print( round( 3.14159, 2 ) ) # 输出3.14Note that this function is not \ (math \) library
Tuple function
What is it, that forms part of the integer part plus float tuple
print( math.modf( 22.7 ) )Returns the integer portion of the floating-point and floating-point numbers are part
although there will be Kichiku accuracy error ......
Prescribing function
I wrote the above
print( math.sqrt( 16 ) )Return is still float
Random number function
There are a lot of random number function
Be sure to call before using \ (random \) library
\ (choice \) function
From the elements of a sequence in a randomly selected
can also pick a string, you can also mix and match
print( random.choice( [ 1, 3, 5, 7, 9, "屁桃" ] ) )
print( random.choice( range( 5 ) ) ) #range(5) == [ 0, 1, 2, 3, 4 ]However, note that if write it like this, then the string will not be seen as an element, but each letter as an element
print( random.choice( "aCutePig" ) )\ (randrange \) function
From the specified range, the radix number is incremented selected from
print( random.randrange( 1, 100, 5 ) )From \ (1 \) to \ (99 \) , select \ (1 + 5n \) number, for example, \ (6,11,16,21 \)
print( random.randrange( 1, 100, 2 ) )Select \ (1,3,5,7 \) , etc.
Start of range and base can not write, began to default is 0, the default is 1 base
\ (random \) function
Less than a randomly generated \ (1 \) greater than or equal \ (0 \) floating point
print( random.random() )\ (shuffle \) function
Upset (easy to understand
list = [ 1, 2, 3, 4, 5 ] #生成一个列表
random.shuffle( list ) #打乱列表元素顺序\ (uniform \) function
Generating a section closed arbitrary real number (integer or floating point within
, of course, and compared endless float, integer number seems too poor
I \ (1 \) to \ (100 \) between the generated \ ( 100 \) number not an integer (character issues do not rule out
print( random.uniform( 1, 100 ) )