Comparison between the two array elements JAVA (to identify the same or different elements)
Reprinted from https://blog.csdn.net/qq_35792598/article/details/76149552
1, to find the same elements in two arrays
public static Set<Integer> getIds(Integer[] a, Integer[] b){
Set<Integer> same = new HashSet<Integer>(); //用来存放两个数组中相同的元素 Set<Integer> temp = new HashSet<Integer>(); //用来存放数组a中的元素 for (int i = 0; i < a.length; i++) { temp.add(a[i]); //把数组a中的元素放到Set中，可以去除重复的元素 } for (int j = 0; j < b.length; j++) { //把数组b中的元素添加到temp中 //如果temp中已存在相同的元素，则temp.add（b[j]）返回false if(!temp.add(b[j])) same.add(b[j]); } return same; } public static void main(String[] arg){ Integer[] array1 = {1,2,3,4,1,2,4,6,7,8,10,22,33}; Integer[] array2 = {1,2,3,4,1,2,4,6,7,8,10,22,33,55,66,77,88,99}; Set<Integer> sameElementSet = getIds(array1,array2); for(Integer i : sameElementSet) { System.out.println(i); } }
Output:
1
2
33
3
4
6
22
7
8
10
2, two arrays are not identify like elements
public static <T> List<T> compare(T[] t1, T[] t2) {
List<T> list1 = Arrays.asList(t1); //将t1数组转成list数组
List<T> list2 = new ArrayList<T>();//用来存放2个数组中不相同的元素 for (T t : t2) { if (!list1.contains(t)) { list2.add(t); } } return list2; } public static void main(String[] arg){ Integer[] array1 = {1, 2, 3}; Integer[] array2 = {1, 2, 3, 4,44}; List<Integer> list = compare(array1,array2); for (Integer integer : list) { System.out.println(integer); } }
Output:
4
44
supplement
Compare two arrays are not the same elements, should traverse more, and then take less in comparison with the number of traversal.
: for (T t multi) {
IF {(less .Contains (t)!)
; different set .add (t)
}
}
: wherein
multilocular set
less is set smaller
elements t of the set of multiple
do not put the same collection is not the same set of elements