Questions algorithms improve results Sort 2
Resource constraints
Time limit: 1.0s memory limit: 256.0MB
problem description
given n student achievement, these students will be sorted by score, collation: High score first; the same score, the higher math scores in the former; Mathematics and the same score, a high front English; English mathematics scores are the same, the former small school number
input format for
the first line of a positive integer n, the number of students
next n lines each of 0 to 100 3 integer i-th row represents the number of students in the school i math, English, language scores
output format
output n rows, each row represents a student's math, English scores, language scores, student number
in the order sorted output
sample input
2
. 1 2. 3
2. 3. 4
sample output
2 2. 4. 3
. 1 2. 3. 1
data size and conventions
n≤100
package com.company;
import java.util.Arrays;
import java.util.Scanner;
public class 成绩排序2 {
public static class Students implements Comparable {
int Math;
int English;
int Chinese;
int Num;
int Sum;
@Override
public String toString() {
return this.Math + " " + this.English + " " + this.Chinese + " " + this.Num;
}
@Override
public int compareTo(Object o) {
Students s = (Students) o;
if (this.Sum > s.Sum) {
return 1;
} else if (this.Sum == s.Sum && this.Math > s.Math) {
return 1;
} else if (this.Sum == s.Sum && this.Math == s.Math && this.English > s.English) {
return 1;
} else if (this.Math == s.Math && this.English == s.English && this.Sum == s.Sum && this.Num < s.Num) {
return 1;
}
return -1;
}
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
Students[] students = new Students[n];
for (int i = 0; i < n; i++) {
Students stu = new Students();
stu.Math = sc.nextInt();
stu.English = sc.nextInt();
stu.Chinese = sc.nextInt();
stu.Num = i + 1;
stu.Sum = stu.Math + stu.English + stu.Chinese;
students[i] = stu;
}
Arrays.sort(students);
for (int i = n - 1; i >= 0; i--)
System.out.println(students[i].toString());
}
}