Find the specified elements in the array

This problem required to achieve a simple lookup function specified elements in the array.

Function interface definition:

int search( int list[], int n, int x );

List where [] is an array of incoming user; n (≥0) is List [] number of elements; x is element be searched. If you find

Search function returns the minimum index of the corresponding element (index starts from 0), -1 otherwise.

Referee test program Example:

#include <stdio.h>
#define MAXN 10

int search( int list[], int n, int x );

int main()
{
    int i, index, n, x;
    int a[MAXN];

    scanf("%d", &n);
    for( i = 0; i < n; i++ )
        scanf("%d", &a[i]);
    scanf("%d", &x);
    index = search( a, n, x );
    if( index != -1 )
        printf("index = %d\n", index);
    else
        printf("Not found\n");

    return 0;
}

/* 你的代码将被嵌在这里 */

Sample Input 1:

5
1 2 2 5 4
2

Output Sample 1:

index = 1

Sample Input 2:

5
1 2 2 5 4
0

Output Sample 2:

Not found

int search( int list[], int n, int x )
{
	int j;
	for(j=0;j<n;j++)
	{
		if(x==list[j])
		    return j;
	}
	return -1;
}