CF1A-Theatre Square

CF1A-Theatre Square

1. Meaning of the questions: \ (the n-* m \) paved area \ (a * a \) bricks, requires a minimum of number.

2. Ideas: to the rounded, \ (ANS = ((n-+. 1-A) / A) * ((m +. 1-A) / A) \)

3. Code:

   #include<bits/stdc++.h>
   using namespace std;
   typedef long long ll;
   int main(void){
       ll n,m,a;
       cin >> n >> m >> a;
       cout<<((n+a-1)/a)*((m+a-1)/a)<<endl;
       return 0;
   }