1022 D hexadecimal A + B (20 minutes)

#include <iostream>

using namespace std;

int main()
{
    long long int a,b,c;
    int d,i=0;
    int num[32];
    cin>>a>>b>>d;
    c=a+b;
    if(c==0)
    {
        cout<<"0"<<endl;
        return 0;
    }
    while(c>0)
    {
        num[i]=c%d;
        c=c/d;
        i++;
    }
    for(int j=i-1;j>=0;j--)
        cout<<num[j];
    return 0;
}

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Origin www.cnblogs.com/QRain/p/12228857.html