Letters graphics _ Blue Bridge Cup

Note: StringBuilder.reverse () after inverting the original string and will write the address of the original string, numeric characters can be converted to use the cast

　　How to say both to understand it, feel this question poisonous!

　　An understanding that, if five words, it is "ABCDEDCBABCDE" taken a continuous cycle length above five strings. Another is to be understood that, taken from the "ZYX ... CBABC ... XYZ" character string length of five

/ ** 
problems described 
using letters may be composed of some beautiful graphics, an example is given below: 
    
    ABCDEFG 
    
    BABCDEF 
    
    CBABCDE 
    
    DCBABCD 
    
    EDCBABC 

This is a pattern row 5 7, find the pattern of this rule, and outputs a n row m graphic column. 

Input format 
    input line, comprising two integers n and m, respectively represent the number of columns you want output line pattern. 
Output format 
    output n lines, each m characters, for your pattern. 
Input Sample 
    57 
Sample Output 
    ABCDEFG 
    BABCDEF 
    CBABCDE 
    DCBABCD 
    EDCBABC 
data size and Conventions 
    1 <= n, m <= 26. 
 * / 
Package jiChuLianXi; 

Import java.util.Scanner; 

public  class LetterFig { 

//     public static void main (String [] args) {
//        // TODO Auto-generated method stub
//        Scanner in = new Scanner(System.in);
//        int n = in.nextInt(), m = in.nextInt();
//        String constStr = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
//        StringBuilder str = new StringBuilder(constStr.substring(0, m));
//        StringBuilder s = new StringBuilder(str.toString());
//        s.append(str.reverse().substring(1));
//        s.append(str.reverse().substring(1));
////        System.out.println(s.length()-m);
//        int sumLines = s.length()-m;
//        for(int j=0; j<n; j++){
////            System.out.println(":" + (sumLines-j%sumLines) + " " + (sumLines-j%sumLines+m));
//            System.out.println(s.substring(sumLines-j%sumLines, sumLines-j%sumLines+m));
//        }
//        in.close();
//    }
    public static void main(String[] args) {
        Scanner sc=  new Scanner(System.in);
        int n = sc.nextInt();//接收行数
        int m = sc.nextInt();//接收列数 
        //将A-Z放入a[]中
        int[] a = new int[26];
        char s = 'A';
        for(int i=0;i<26;i++) { 
            a[i] = s+i;
        }
        //循环
        for(int i=0;i<n;i++) {
            for(int j=i;j>=i-m+1&&j>-1;j--) {
                System.out.print((char)a[j]);
            }
            for(int k=1;k<=m-i-1;k++) {
                System.out.print((char)a[k]);//数字转化为字符+
            }
            System.out.println();
        }
}}
/**
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner sc=  new Scanner(System.in);
        int n = sc.nextInt();//接收行数
        int m = sc.nextInt();//接收列数 
        //将A-Z放入a[]中
        int[] a = new int[26];
        char s = 'A';
        for(int i=0;i<26;i++) { 
            a[i] = s+i;
        }
        //循环
        for(int i=0;i<n;i++) {
            for(int j=i;j>=i-m+1&&j>-1;j--) {
                System.out.print((char)a[j]);
            }
            for (int. 1 = K; K <= mi The-. 1; K ++) {
                System.out.print ((char) a [k ]); // number into character 
            } 
            System.out.println (); 
        } 
        
    } 
} 
 * /