To give you an array of integers nums, you return to where the median of an even number of numbers.
Example 1:
Input: nums = [12,345,2,6,7896]
Output: 2
Explanation:
12 is a 2-digit number (the number of bits is an even number)
345 3 digits (digits is odd)
2 is a 1-bit digital (odd digits)
6 is an odd number of digits)
7896 is 4 digits (bits the number is an even number)
so only 12, and 7896 is the number of bits is an even number
Example 2:
Input: nums = [555,901,482,1771]
Output: 1
Explanation:
Only 1771 was a median of numbers even.
Problem solving:
Using the string:
public int findNumbers(int[] nums) {
int count = 0;
for (int num : nums)
count += String.valueOf(num).length() % 2 == 0 ? 1 : 0;
return count;
}
Mathematics / 10
public int findNumbers(int[] nums) {
int count = 0;
for (int num : nums) {
int n = 0;
while (num > 0) {
num /= 10;
n++;
}
count += n % 2 == 0 ? 1 : 0;
}
return count;
}