Embed code
<iframe id="LTTP" width="80%" onload='this.height=document.getElementById("LTTP").scrollWidth*0.75+"px"' frameborder="0" src='https://www.desmos.com/calculator/pwowcxjsiw?embed' style="border: 1px solid #ccc"></iframe>
Abstract pictures
<img class="desc_img" src="https://images.cnblogs.com/cnblogs_com/wanghai0666/1538550/o_Cnblogs_zytp_14.jpg">
Editing code
<LT>例1</LT>
Feed code
<div STYLE="page-break-after: always;"></div>
Choice of code
<div class="Grid"><div class="Grid-cell">$A.\alpha内有无数条直线与\beta平行$</div><div class="Grid-cell">$B.\alpha内有两条相交直线与\beta平行$</div></div><div class="Grid"><div class="Grid-cell">$C.\alpha,\beta平行于同一条直线$</div> <div class="Grid-cell">$D.\alpha,\beta垂直于同一个平面$</div></div>
Conic
$\cfrac{x^2}{a^2}+\cfrac{y^2}{b^2}=1(a>b>0)$
Piecewise functions
$\left\{\begin{array}{l}{x=1}\\{y=1}\\{z=3}\end{array}\right.$
$f(x)=\left\{\begin{array}{l}{x=1}\\{y=1}\end{array}\right.$
Multiple-choice options
<div class="XZXX" >$A.0.7$ $B.0.6$ $C.0.4$ $D.0.3$</div>
<div class="XZXX" >$A.f(\cfrac{3}{2})>f(2)>f(3)$ $B.f(3)>f(2)>f(\cfrac{3}{2})$ $C.f(\cfrac{3}{2})>f(3)>f(2)$ $D.f(3)>f(\cfrac{3}{2})>f(2)$</div>
<div class="XZXX" >$A.a < b < c$ $B.a < c < b$ $C.b < c < a$ $D.c < a < b$</div>
<div class="XZXX" >$A.(-\infty,0)$ $B.(0,+\infty)$ $C.(1,+\infty)$ $D.(-\infty,1)$</div>
<div class="XZXX" >$A.[2,6]$ $B.[4,8]$ $C.[\sqrt{2},3\sqrt{2}]$ $D.[2\sqrt{2},3\sqrt{2}]$</div>
<div class="XZXX" >$A.[2,6]$ $B.[4,8]$ $C.[\sqrt{2},3\sqrt{2}]$ $D.[2\sqrt{2},3\sqrt{2}]$</div>
<div class="XZXX" >$A.f(\cfrac{3}{2})>f(2)>f(3)$ $B.f(3)>f(2)>f(\cfrac{3}{2})$ $C.f(\cfrac{3}{2})>f(3)>f(2)$ $D.f(3)>f(\cfrac{3}{2})>f(2)$</div>
1、<a href="https://www.cnblogs.com/wanghai0666/p/9613192.html " target="_blank">由抽象函数不等式求参数的取值范围</a>;
<div class="XZXX" >$A.[1,+\infty)$ $B.(1,+\infty)$ $C.[2,+\infty)$ $D.(2,+\infty)$</div>
<div class="XZXX" >$A.[\cfrac{1}{6},1]$ $B.[\cfrac{2}{13},1]$ $C.[\cfrac{1}{6},\cfrac{4}{13}]$ $D.[\cfrac{1}{6},2\sqrt{2}]$</div>