Title Description
A frog can jump on a Class 1 level, you can also hop on level 2 ... n it can also jump on stage. The frog jumped seeking a total of n grade level how many jumps.
Problem-solving ideas
Dynamic Programming
public int JumpFloorII(int target) { int[] dp = new int[target]; Arrays.fill(dp,1); for(int i =1;i<target;i++) for(int j =0;j<i;j++) dp[i] += dp[j]; return dp[target-1]; }
Mathematical derivation
Jump stairs n-1, n-2 can jump from level 1 up stage, may jump up from the two-stage n-3 ..., then
f(n-1) = f(n-2) + f(n-3) + ...+ f(0)
Also, jump n steps, can jump up from level 1 level n-1, stage 2 may jump from the n-2 ... up stage, then
f(n) = f(n-1) + f(n-2) + ... +f(0)
In summary available
f(n) - f(n-1) = f(n-1)
which is
f(n) = 2*f(n-1)
Therefore, f (n) is a geometric sequence
public int JumpFloorII(int target) { return (int) Math.pow(2, target - 1); }