Figure
Complete binary (presence of a single branch) corresponding to the binary list
Seeking null child pointer field that is required to re-node point number × 2 + 1 (where 1 is the single branch nodes null pointer domain)
8 is a front depth complete binary tree is a full binary tree layer 9, a total of 2⁸-1 = 255 nodes
Ninth layer nodes 500-255 = 245 (found 245 odd parent node must have a single branch), the number of parent node 244/123 = 1 + 2 (which has a single branch node)
8th layer 2⁷ = 128 nodes, wherein the number of leaf nodes 128-123 = 5 (see figure do not understand)
Therefore, the number of null pointer field = 245 × 2 + 5 × 2 + 1 = 501 th
Pure hand is not easy to play, want to help