java programming language ** 10.25 CHAPTER X class exercises string split function to achieve

** 10.25 split method (split method new String) String class returns a string array, which is separated by the delimiter string configuration. However, this separator is not returned. New Method for the following implementation, the method returns a string array that matches a string of characters separated configuration, also includes a matching character string.

public static String[] split(String s,String regex)

For example, split ( "ab # 12 # 453", "#") returns ab, #, 12, #, and 453 String array configuration, the split ( "a? B? Gf # e", "[? #] ") returns a ,? , B ,? , Gf, # e, and string array configuration.

//package example4;
import java.io.*;
import java.util.*;
import java.util.regex.*;
public class ex5 {

    public static String[] split(String s,String regex) {
        ArrayList<String> matchList = new ArrayList<String>();
        Pattern pat = Pattern.compile(regex);  
        Matcher mat = pat.matcher(s);
        int index = 0;
        while(mat.find()) {
                String match = s.subSequence(index, mat.start()).toString();
                matchList.add(match);
                String match2 = s.subSequence(mat.start(),mat.end()).toString();
                matchList.add(match2);
                index = mat.end();
        }
        String match = s.subSequence(index,s.length()).toString();
        matchList.add(match);
        
        int resultSize = matchList.size();
        while (resultSize > 0 && matchList.get(resultSize-1).equals(""))
            resultSize--;
        String[] result = newString [ResultSize];
         return matchList.subList (0 , ResultSize) .toArray (Result); 
        } 
    public  static  void main (String [] args) { 
        String [] ANS = Split ( "ab & # 123 # 453", "#" ); 
        System.out.println ( "pattern string as" ab # 123 # 453 ", matching string is" # "matching result string array is:" );
         for ( int I = 0; I <ans.length; I ++ ) { 
            System.out.println (ANS [I]); 
        } 
        String [] ANS2 = Split ( "GF # A B E??", "[#?]" ); 
        System.out.println ( "pattern string is "?? a b gf # e ", the matching string is "[? #]" matching result string array is: " );
        for(int i=0;i<ans2.length;i++) {
            System.out.println(ans2[i]);
        }
    }
    
}