Title: Integrated Student Information System Assessment
Procedural requirements
Information for each student: Student ID, name, gender, home address, telephone number, language, mathematics, foreign languages three single subject results, average test scores, ranking exam, students score each other, moral achievement, classroom teachers score, comprehensive assessment scores, comprehensive evaluation ranking. Average test scores, students score each other, moral achievement, classroom teachers comprehensive evaluation score 60% of the total score, 10%, 10%, 20%, respectively.
A , student information processing
(1) input student information, student number, name, gender, home address, telephone number, student number by small to large order into the file.
(2) is inserted (modified) students information:
(3) Delete the students information:
(4) View Student Information:
B , student data processing :
(1) entry by test subjects and student achievement according to the formula:
Test scores = (foreign language + mathematics +) / 3 to calculate test scores, and calculate the test rankings, tips: first student information read into the array, and then follow the prompts to enter grades for each subject, calculate test scores to determine the ranking of the last students record written to a file.
(2) Student Assessment data input and calculates the comprehensive evaluation score and ranking.
Comprehensive evaluation score = (test scores) * 0.6 + (peer response rate) * 0.1 + 0.1 * + and moral achievements instructor rating * 0.2.
(3) student data management
Enter school, the students read and displayed information, enter new data, the file information is written after change
(4) student data query:
Enter the student number, or other information, i.e., all the data is read out and displayed.
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博主VX：15813406574，永久在线，承接JAVA、C\C++、python、matlab等课程设计博主VX：15813406574，永久在线，承接JAVA、C\C++、python、matlab等课程设计
Then there is the effect chart shows:
Shows the core code (because of space limitations here only shows part of the code, if you need all the code can whisper)
void data_xiugai() //数据修改
{
int pp;
int i,j,k;
data_daoru();
printf("\n\t请输入要修改学生的学号：");
scanf("%d",&pp);
printf("\n");
for(i=0;i<=count;i++){
if(data[i].number==pp) break;
}
if(i>=count) { printf("\n\t没有找到该学生!\n"); return;}
printf("\n\t学号:%.0d 姓名:%s \n\n\t语文:%d 数学:%d 英语:%d 品德成绩:%d 老师评分:%d\n\n",data[i].number,info[i].name,data[i].chinese,data[i].math,data[i].english,data[i].pinde,data[i].teacher);
printf("\n\t是否修改?\t 1.是 \t 2.否 \t ");
while(1){ //询问
scanf("%d",&j);
switch(j){
case 1:{
for(k=0;k<=count;k++){ //重新排名次
if(data[i].avg>data[k].avg) data[k].ksmc=data[k].ksmc-1;
}
printf("\n\t请输入语文成绩：");
scanf("%d",&data[i].chinese);
while( data[i].chinese < 0 || data[i].chinese > 100 )
{ printf("\t对不起你输入的数据不是 1-100 之间，请从新输入真确的数值！\n");
printf("\t请输入老师评分：");
scanf("%d",&data[i].chinese );
}
printf("\t请输入数学成绩：");
scanf("%d",&data[i].math);
while( data[i].math < 0 || data[i].math > 100 )
{ printf("\t对不起你输入的数据不是 1-100 之间，请从新输入真确的数值！\n");
printf("\t请输入数学成绩：");
scanf("%d",&data[i].math);
}
printf("\t请输入英语成绩：");
scanf("%d",&data[i].english);
while( data[i].english < 0 || data[i].english > 100 )
{ printf("\t对不起你输入的数据不是 1-100 之间，请从新输入真确的数值！\n");
printf("\t请输入英语成绩：");
scanf("%d",&data[i].english);
}
printf("\n\t请输入同学互评成绩：");
scanf("%d",&data[i].huping );
while( data[i].huping < 0 || data[i].huping > 100 )
{ printf("\t对不起你输入的数据不是 1-100 之间，请从新输入真确的数值！\n");
printf("\t请输入同学互评成绩：");
scanf("%d",&data[i].huping );
}
printf("\n\t请输入品德成绩：");
scanf("%d",&data[i].pinde);
while( data[i].pinde < 0 || data[i].pinde > 100 )
{ printf("\t对不起你输入的数据不是 1-100 之间，请从新输入真确的数值！\n");
printf("\t请输入品德成绩：");
scanf("%d",&data[i].pinde);
}
printf("\t请输入老师评分：");
scanf("%d",&data[i].teacher);
while( data[i].teacher < 0 || data[i].teacher > 100 )
{ printf("\t对不起你输入的数据不是 1-100 之间，请从新输入真确的数值！\n");
printf("\t请输入老师评分：");
scanf("%d",&data[i].teacher);
}
data[i].avg=(data[i].chinese+data[i].math+data[i].english)/3.0;
data[i].ceping=(data[i].avg*0.6+data[i].huping *0.1+ data[i].pinde*0.1+data[i].teacher*0.2);
data[i].ksmc=count;
for(k=0;k<count;k++){ //重新排名次
if(data[i].avg>data[k].avg){
data[k].ksmc=data[k].ksmc+1;
if(data[i].ksmc>data[k].ksmc-1)
data[i].ksmc=data[k].ksmc-1;
}
}
printf("\n\t修改成功!\n\n"); data_xieru(); return; //写入文件
}
case 2: return;
default : printf("输入错误!请重新输入!");break;
}
break;
}
printf("\n\n\t\t");
system("pause");
}