Given a string of characters printed output is not repeated and the number of repetitions, and the number of repetitions in accordance with the output ascending

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The beginning looked very simple, say you want to sort later, remembering the comparator inside with a custom Collections

 

Code:

public class StringDemo {
    public static void main(String[] args) {
        String str = "asdzxasdqweasdzs";
        char[] chars = str.toCharArray();
        Map<Character, Integer> map = new HashMap<>();
        for (char ch : chars) {
            if (map.containsKey(ch)) {
                map.put(ch, map.get(ch) + 1);
            } else {
                map.put(ch, 1);
            }
        }
        System.out.println("map:" + map);
        //排序
        List<Map.Entry<Character, Integer>> list = new ArrayList<>();
        for (Map.Entry<Character, Integer> entry : map.entrySet()) {
            list.add(entry);
        }
        
        Collections.sort(list, new Comparator<Map.Entry<Character, Integer>>() {
            @Override
            public int compare(Map.Entry<Character, Integer> o1, Map.Entry<Character, Integer> o2) {
                return o1.getValue() - o2.getValue();
            }
        });
        System.out.println("排序后:" + list);
    }
}

结果:
map:{a=3, q=1, s=4, d=3, e=1, w=1, x=1, z=2}
排序后:[q=1, e=1, w=1, x=1, z=2, a=3, d=3, s=4]

  

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Origin www.cnblogs.com/cmmplb/p/11963518.html