Python container type of operation set

Collection (set): is a collection of unordered sequence, the set of elements can be any data type; manifestation is set (set of elements), the automatic de-duplication; must be a set of incoming hashable type value, (value can not be stored in the dictionary format); and creating a set time is not able to represent this set1 = {}, this representation is not an empty set, which means that the dictionary is empty;

1. Create a collection

Declared directly #: 
setl = {1,2,3,4} 

List1 = [1,2,3,4,1,2,3,4 ] 
setl = SET (List1)    # list incoming 
Print (setl)          # return value: {1, 2, 3, 4}

2. The collection of operational relations

Intersection: Take two identical sets of elements constituting a new set

# Set intersection of 
setl = {1,2,3,4,5,6, ' C ' , ' D ' } 
SET2 = { ' A ' , ' B ' , ' C ' , ' D ' , 1,6 }
 Print (setl & SET2)   # returned result is: {1, 'c', 'd', 6}

And Set: taking all the elements constituting two sets of a new set of identical elements removed

# Set request and sets 
setl = {1,2,3,4,5,6, ' C ' , ' D ' } 
SET2 = { ' A ' , ' B ' , ' C ' , ' D ' , 1,6 }
 Print (setl | SET2)   # returned as the result: { 'b', 1, 2, 3, 4, 5, 6, 'a', 'd', 'c'}

Difference-set: -B A collection of collection, the collection element A is removed in set B, set A only taking element is not set B, and generates a new set

# Set of differencing sets 
setl = {1,2,3,4,5,6, ' C ' , ' D ' } 
SET2 = { ' A ' , ' B ' , ' C ' , ' D ' , 1,6 }
 Print (setl - SET2)   # returned result is: {2, 3, 4, 5}

Non-collection: taking intersection of two sets, then taken in accordance with the complement of the intersection of the two sets, and finally set taking complement

# Set of non-seeking set 
setl = {1,2,3,4,5,6, ' C ' , ' D ' } 
SET2 = { ' A ' , ' B ' , ' C ' , ' D ' , 1,6 }
 Print (setl ^ SET2)   # returns the result of: {2, 3, 4, 5, 'a', 'b'}

3. The method of determining a set of

# Judge whether this collection is collection contains additionally
 Print (set1.issubset (set2)) # If set2 set1 collection element contains a True otherwise it returns False 
# judge whether this collection contains another collection 
Print (set1.issuperset (set2 )) # If set1 set2 collection element contains a True otherwise it returns False 
# If the intersection of two sets is empty returns True 
Print (set1.isdisjoint (set2))