C # -like str.LastIndexOf ()
There cell A1
12345#78#abc#ef
Finally, a # number position in the string:
1. First, there are several statistical A1 #
# Replace the null, then the new string length minus the original length of the string, i.e. the number #
If you are looking for more than a string of characters, is divided by a long string
=LEN(A1)-LEN(SUBSTITUTE(A1,"#",""))
2. The original string in the last # with a special symbol, such as @ replaced.
@ Needs is A1 has never seen before
=SUBSTITUTE(A1,"#","@",LEN(A1)-LEN(SUBSTITUTE(A1,"#","")))
SUBSTITUTE third parameter is the number of A1, @ # replaced,
The last # is the number of a total number of #
At this point A1, says:
12345#78#abc@ef
3. Find @ again to the position of a value of 13.
=FIND("@",SUBSTITUTE(A1,"#","@",LEN(A1)-LEN(SUBSTITUTE(A1,"#",""))))
