C ++ white of the road - the number seeking quality

Beginner C ++, intended to learn footprint with blog record. Write a program seeking two prime numbers, minor changes.

. 1 #include <the iostream>
 2 #include <math.h>
 . 3  the using  namespace STD;
 . 4  int main () {
 . 5      int m, n-, K, I, J, H;
 . 6      n-= 0 ;   // n-should not be defined within the outer loop, or can not achieve the effect of line feed 
. 7      CIN >> m;
 . 8      // start I k is defined in vitro cycle, leading to failure and will change as the value of k after each inner loop, the outer loop to be repeated defined 
. 9      for (I = . 1 ; I <= m; I ++ ) 
 10      {
 . 11          K = . 1 ;       // may be provided Boolean effect, k value the same as the Boolean     
12 is          H =sqrt (I);
 13 is          for (J = 2 ; J <= H; J ++ )
 14          {
 15              IF (% I J == 0 )
 16              {
 . 17                  K = 0 ;
 18 is                  BREAK ;
 . 19              }
 20 is          }             // BREAK Application the position of the inner loop, comprising a first inner loop if (k) statement, leading to print something less than 
21 is              IF (K)
 22 is              {
 23 is                  COUT I << << "  " ;
 24                  n-+ = . 1 ;
 25                 if (n % 10 == 0)
26                     cout << endl;
27             }
28     
29     }
30     system("pause");
31     return 0;
32 }

 1 #include <iostream>
 2 #include <math.h>
 3 using namespace std;
 4 int minum, maxnum;
 5 int i, j, k;
 6 int main() {
 7     int count = 0;
 8     cout << "请输入两个数：" << endl;
 9     cin >> minum >> maxnum;
10     for(i=minum;i<=maxnum;i++){
11         k = sqrt(i);
12         for (j = 2; j <= k; j++) {
 13 is              IF (i% J == 0 )
 14                  BREAK ;
 15          }
 16          IF (J> = K + . 1 )     // determination condition is whether or not i is a prime number 
. 17          {          
 18 is              COUT << i << "  " ;
 . 19              COUNT ++ ;
 20 is              IF (COUNT% 10 == 0 )
 21 is                  COUT << endl;
 22 is          }           
 23 is      }
 24      System ( " PAUSE");
25     return 0;
26 }