Title Description
Calculated the number of integer of 1 to 13 1 arise, and calculates the number of times an integer from 100 to 1300 in 1 occur? To this end he especially counted about 1 to 13 contains the digits 1 has 1,10,11,12,13 therefore appear a total of six times, but for the problem behind him Meizhe. ACMer hope you will help him, and the problem is more generalized, the number of non-negative integer in the range 1 appears (the number of occurrences from 1 to n. 1) can quickly find any.
Solution:
find the law questions:
find the law questions:
1 class Solution { 2 public: 3 int NumberOf1Between1AndN_Solution(int n) 4 { 5 if (n <= 0)return 0; 6 int left = 0, right = 0, a = 1, now = 1, ans = 0; 7 while (n / a) { 8 left = n / (a * 10), now = n / a % 10, right = n % a; 9 if (now == 0) ans += left * a; 10 else if (now == 1) ans += left * a + right + 1; 11 else ans += (left + 1) * a; 12 a = a * 10; 13 } 14 return ans; 15 } 16 };