[Python] catch the exception

try:
    num = int(input("请输入一个整数:"))
    result = 8 / num
    print(result)
except ValueError:
    print("请输入正确的整数")
except Exception as ret:
    print("未知错误 %s" % ret)

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Origin www.cnblogs.com/liudianer/p/11688733.html