day_14 anonymous function in conjunction with the built-in function job title

'' ' 
Requirements: 
Remove a record from each file into a list, each element of the list ` 
{' name ':' Egon ',' Sex ':' MALE ',' Age ': 18 is,' the salary ': 3000}' forms 
' '' 

all_user_list = [] 
with Open ( ' user_info.txt ' , ' R & lt ' , encoding = ' UTF-. 8 ' ) AS F:
     for per_info in F: 
        per_user_dic = {} 
        name, Sex , Age, the salary = per_info.strip (). Split () 
        per_user_dic [ ' name ']=name
        per_user_dic['sex' ] = Sex 
        per_user_dic [ ' Age ' ] = int (Age) 
        per_user_dic [ ' the salary ' ] = int (the salary) 
        all_user_list.append (per_user_dic) 
    Print (all_user_list)
     # 1. Table 1 obtained according to remove most people pay information 
    Print (max (all_user_list, Key = the lambda per_user_dic: per_user_dic [ ' the salary ' ]))
     # 2. the list 1 was removed youngest person information 
    Print (min (all_user_list, Key = the lambda per_user_dic: per_user_dic [ ' Age ' ]))
    # The resulting list 1, each of the information mapped to the first name uppercase letter 
    Print (List (Map ( the lambda per_user_dic: {per_user_dic [ ' name ' ] .capitalize (): name, per_user_dic [ ' Sex ' ]: Sex, 
                        per_user_dic [ ' Age ' ]: int (Age), per_user_dic [ ' the salary ' ]: int (the salary)}, all_user_list)))
     # 4. according to Table 1, was filtered off names beginning with a person's information 
    Print (List (filter ( the lambda per_user_dic: per_user_dic [ ' name ' ] .startswith ( ' a ' ), all_user_list)))

View Code

# 2. Print recursive Fibonacci number (numbers and the first two to give a third number, such as: 2 0. 1. 1. 4. 3. 7 ...) 

Item = int (INPUT ( ' entry number >>> : ' )) 
Start1 = int (INPUT ( ' starting first number >>>: ' )) 
start2 = int (INPUT ( ' starting second number >>>: ' )) 

DEF FIB (n-, X , Y):
     IF n-== 0:
         return 
    the else : 
        X, Y = Y, X + Y
         Print (Y) 
    FIB (n- -1 , X, Y) 
FIB (Item, Start1, start2)

# 3 a nested list of many layers, such as l = [1,2, [3, [4,5,6, [7,8, [9,10, [11,12,13, [14,15 ]]]]]]], taking out all the values recursively 
l = [1,2, [3, [4,5,6, [7,8, [9,10, [11,12,13, [14 , 15 ]]]]]]] 

DEF get_element (X):
    for I in X:
        IF type (I) == List: 
           get_element (I) 
       the else :
             Print (I) 
get_element (L)