【HDOJ6600】Just Skip The Problem(签到)

Meaning of the questions: Ask n result of mold 1e6 + 7!

n<=1e9

Ideas:

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 typedef long long ll;
 4 typedef unsigned int uint;
 5 typedef unsigned long long ull;
 6 typedef pair<int,int> PII;
 7 typedef pair<ll,ll> Pll;
 8 typedef vector<int> VI;
 9 #define N  110000
10 #define M  1100000
11 #define fi first
12 #define se second
13 #define MP make_pair
14 #define pi acos(-1)
15 #define mem(a,b) memset(a,b,sizeof(a))
16 #define rep(i,a,b) for(int i=(int)a;i<=(int)b;i++)
17 #define per(i,a,b) for(int i=(int)a;i>=(int)b;i--)
18 #define lowbit(x) x&(-x)
19 #define Rand (rand()*(1<<16)+rand())
20 #define id(x) ((x)<=B?(x):m-n/(x)+1)
21 #define ls p<<1
22 #define rs p<<1|1
23 
24 const int MOD=1e6+3;
25       double eps=1e-6;
26       ll INF=1e14;
27 
28 
29 int read()
30 {
31    int v=0,f=1;
32    char c=getchar();
33    while(c<48||57<c) {if(c=='-') f=-1; c=getchar();}
34    while(48<=c&&c<=57) v=(v<<3)+v+v+c-48,c=getchar();
35    return v*f;
36 }
37 
38 int main()
39 {
40     //freopen("1.in","r",stdin);
41     //freopen("1.out","w",stdout);
42     int n;
43     while(scanf("%d",&n)!=EOF)
44     {
45         ll ans=1;
46         if(n>=MOD)
47         {
48             printf("0\n");
49             continue;
50         }
51 
52         rep(i,1,n) ans=ans*i%MOD;
53         printf("%I64d\n",ans);
54     }
55     return 0;
56 }

 

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Origin www.cnblogs.com/myx12345/p/11584078.html