Function overloading C ++ class instance

C ++ overloaded functions in support of, and know what function overloading has several features:

1. C ++ function overloading Review

• Overloaded functions essentially independent of different functions
• By C ++ function name and function parameters determine the function call
• Not directly through the function name to get overloaded function entry address
• Function overloading necessarily occur in the same scope

Function overloading 2. C ++ classes

Class member functions can be overloaded, including

• Overloaded constructor
• Overloaded ordinary member function
• Overloaded static member function

Note: Function Overloading must occur in the same scope, and therefore the class member functions and global functions can not constitute a heavy load.

#include <stdio.h>

class Test
{
    int i;
public:
    Test()
    {
        printf("Test::Test()\n");
        this->i = 0;
    }

    Test(int i)
    {
        printf("Test::Test(int i)\n");
        this->i = i;
    }

    Test(const Test &obj)
    {
        printf("Test(const Test& obj)\n");
        this->i = obj.i;
    }

    static void func()
    {
        printf("void Test::func()\n");
    }

    void func(int i)
    {
        printf("void Test::func(int i), i = %d\n", i);
    }

    int getI()
    {
        return i;
    }
};

void func()
{
    printf("void func()\n");
}

void func(int i)
{
    printf("void func(int i), i = %d\n", i);
}

int main()
{
    func();        // void func()
    func(1);       // void func(int i), i = 1

    Test t;        // Test::Test()
    Test t1(1);    // Test::Test(int i)
    Test t2(t1);   // Test(const Test& obj)

    func();        // void func()
    Test::func();  // void Test::func()

    func(2);       // void func(int i), i = 2;
    t1.func(2);    // void Test::func(int i), i = 2
    t1.func();     // void Test::func()

    return 0;
}

Overloaded meaning

• Prompt function by function name of the function
• Prompt use of the function parameter list
• Expansion of the system already exists in the function function

#include <stdio.h>
#include <string.h>

char *strcpy(char *buf, const char *str, unsigned int n)
{
    return strncpy(buf, str, n);
}

int main()
{
    const char *s = "D.T.Software";
    char buf[8] = {0};

    strcpy(buf, s, sizeof(buf) - 1);

    printf("%s\n", buf);

    return 0;
}